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((-3)/(7))^(-1)...

((-3)/(7))^(-1)

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((3)/(7)z-(1)/(2))/(z-(1)/(4))-(3)/(14)=(1)/(7)

(7^(2))^(3)times[((1)/(7))^(2)]^(3)

The sum of series 2[ 7^(-1)+3^(-1).7^(-3)+5^(-1).7^(-5)+...] is

2[7^(-1)+3^(-1)7^(-3)+5^(-1)7^(-5)+…]=

The sum of series 2[ 7^(-1)+3^(-1).7^(-3)+5^(-1).7^(-5)+...] is

(7)/(8)-(3)/(4)+(1)/(2)=(7-3+1)/(8)=

3((7x+1)/(5x-3))-4((5x-3)/(7x+1))=11;x!=(3)/(5),-(1)/(7)

{:("Quantity A","Quantity B"),((1)/(3)+(1)/(4)+(7)/(12),(1)/((1)/(3)+(1)/(4)+(7)/(12))):}

Solve the quadratic equation by factorisation: 3((7x+1)/(5x-3))-4((5x-3)/(7x+1))=11 x != 3//5, x != 1//7