Nucleus A decays into B with a decay constant `lamda_(1)` and B further decays into C with a decay constant `lamda_(2)` . Initially, at t = 0, the number of nuclei of A and B were `3N_(0)` and `N_(0)` respectively. If at t = `t_(0)` number of nuclei of B becomes constant and equal to `2N_(0)`, then

Nucleus A decays to B with decay constant lambda_(1) and B decays to C with decay constant lambda_(2) . Initially at t=0 number of nuclei of A and B are 2N_(0) and N_(0) respectively. At t=t_(o) , no. of nuclei of B is (3N_(0))/(2) and nuclei of B stop changing. Find t_(0) ?

Nucleus A decays to B with decay constant lambda_(1) and B decays to C with decay constant lambda_(2) . Initially at t=0 number of nuclei of A and B are 2N_(0) and N_(0) respectively. At t=t_(o) , no. of nuclei of B is (3N_(0))/(2) and nuclei of B stop changing. Find t_(0) ?

Nucleus A decays to B with decay constant lamda_(1) and B decuys to C with decay constants lamda_(2) . Initially at t=0, number of nuclei of A and B are 2N_(0) and N_(0) respectively. At some instant t=t_(0) , number of nuclei of B stop changing. Find t_(0) if at this intant number of nuclei of B is (3N_(0))/(2)

Two radioactive materials A & B have decay constant 3lamda and 2lamda respectively. At t=0 the numbers of nuclei of A and B are 4N_(0) and 2N_(0) respectively then,

Two radioactive materials A & B have decay constant 3lamda and 2lamda respectively. At t=0 the numbers of nuclei of A and B are 4N_(0) and 2N_(0) respectively then,

A radioactive element A of decay constant lamda_(A) decays into another radioactive element B of decay constant lamda_(B) . Initially the number of active nuclei of A was N_(0) and B was absent in the sample. The maximum number of active nuclei of B is found at t=2. In 2//lamda_(A) . The maximum number of active nuclei of B is

A radioactive element A of decay constant lamda_(A) decays into another radioactive element B of decay constant lamda_(B) . Initially the number of active nuclei of A was N_(0) and B was absent in the sample. The maximum number of active nuclei of B is found at t=2. In 2//lamda_(A) . The maximum number of active nuclei of B is

A radioactive substance "A" having N_(0) active nuclei at t=0 , decays to another radioactive substance "B" with decay constant lambda_(1) . B further decays to a stable substance "C" with decay constant lambda_(2) . (a) Find the number of nuclei of A, B and C time t . (b) What should be the answer of part (a) if lambda_(1) gt gt lambda_(2) and lambda_(1) lt lt lambda_(2)

A radioactive substance "A" having N_(0) active nuclei at t=0 , decays to another radioactive substance "B" with decay constant lambda_(1) . B further decays to a stable substance "C" with decay constant lambda_(2) . (a) Find the number of nuclei of A, B and C time t . (b) What should be the answer of part (a) if lambda_(1) gt gt lambda_(2) and lambda_(1) lt lt lambda_(2)