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I(m,n)^( prime)=int(0)^( pi/2)sin^(m)x c...

I_(m,n)^( prime)=int_(0)^( pi/2)sin^(m)x cos^(n)xdx" then "I_(m,n)=(m-1)/(m+n)I_(m-2,n^(*))

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If I_(m;n)=int_(0)^((pi)/(2))sin^(m)x cos^(n)xdx then show that I_(m;n)=(m-1)/(m+n)I_(m-2;n) and find I_(m;n) in terms of different combinations of m and n.

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