The perpendicular bisector of `x+y+2=0 and x -y-1 = 0` of sides AB and AC of a `DeltaABC` intersects them at `(-1,-1) and (2, 1)` respectively. If the mid-point of side BC is P, then distance of this point from the orthocentre of triangle is

The sides AB and AC of a triangle ABC are respectively 2x+3y=29 and x+2y=16 respectively.If the mid-point of BC is (5,6) then find the equation of BC

The sides AB and AC of a triangle ABC are respectively 2x+3y=29 and x+2y=16 respectively.If the mid-point of BCis(5,6) then find the equation of BC.

Mid-points of the sides AB and AC of a DeltaABC are (3, 5) and (-3, -3) respectively, then the length of the side BC is

The equations of perpendicular bisectors of the sides AB and AC of a DeltaABC are x - y + 5 = 0 and x+2y = 0 , respectively. If the point A is (1, - 2) the equation of the line BC is

In a triangle, ABC, the equation of the perpendicular bisector of AC is 3x - 2y + 8 = 0 . If the coordinates of the points A and B are (1, -1) & (3, 1) respectively, then the equation of the line BC & the centre of the circum-circle of the triangle ABC will be