A particle of mass 0.50 kg executes a simple harmonic motion under a force F = – (50 N/m)x. If it crosses the centre of oscillation with a speed of 10 m/s, find the amplitude of the motion.

A particle of mass 0.50 kg executes a simple harmonic motion under a forve F = -(50 n//m)x . If crosses the centre of oscillation with a speed of 10 m//s , find the amplitude of the motion.

A particle of mass 0.50 kg executes a simple harmonic motion under a force F=-(50Nm^-1)x . If it crosses the centre of oscillation with a speed of 10ms^-1 , find the amplitude of the motion.

A particle of mass 0.50 kg executes a simple harmonic motion under a force F=-(50Nm^-1)x . If it crosses the centre of oscillation with a speed of 10ms^-1 , find the amplitude of the motion.

A particle of mass 0.50 kg executes a simple harmonic motion under a force F=-(50Nm^-1)x . If it crosses the centre of oscillation with a speed of 10ms^-1 , find the amplitude of the motion.

A particle executes simple harmonic motion of period 16 s . Two seconds later after it passes through the center of oscillation its velocity is found to be 2 m//s . Find the amplitude.

A particle executes simple harmonic motion of period 16 s . Two seconds later after it passes through the center of oscillation its velocity is found to be 2 m//s . Find the amplitude.

A particle of mass 0.2 kg executes SHM under a force of F = - 20x N. If speed of particle at mean position is 12 m/s then the amplitude of oscillations is