A compound AB crystallizes in bcc lattice with unit edge length of 380 pm. Calculate (i)The distance between oppositely charged ions in the lattice.
(ii)Radius of `A^+` if radius of B is 175 pm

A compound AB crystallines in bcc lattice with unit cell edge length of 380 pm. Calculate the distance between oppositely charged ions in the lattice.

A compound AB crystallises in bcc lattice with the unit cell edge length of 380 pm . Calculate (i) The distance between oppositely charged Ions in the lattic. (ii)Radius of B^(−) if the radius of A^(+) is 190 pm.

A compound 'A B' crystallises in bcc lattice.with unit cell.edge length of '380 pm'. Calculate' (i) -the distance between oppositely charged ions (ii) radius of 'A^+' if radius of 'B^-' is in the lattice '175 pm' (c fits exactly in the cubic void)

A compound AB crystallises in the b.c.c lattice with unit cell edge length of 390 pm. Calculate (a) the distance between the oppsitely charged ions in the lattice. (b) the radius of A^(+) ion if radius of B^(-) ion is 175 pm.

A compound AB crystallises in the b.c.c lattice with unit cell edge length of 390 pm. Calculate (a) the distance between the oppsitely charged ions in the lattice. (b) the radius of A^(+) ion if radius of B^(-) ion is 175 pm.

A compound AB crystallises in the b.c.c lattice with unit cell edge length of 390 pm. Calculate (a) the distance between the oppsitely charged ions in the lattice. (b) the radius of A^(+) ion if radius of B^(-) ion is 175 pm.

AB crystallises in a bcc lattice with edge length ‘a’ equal to 387 pm. The distance between two oppositely charged ions in the lattice is

AB crystallises in a bcc lattice with edge length qa equal to 387 pm .The distance between two oppositely chariged ions in the lattice is