[" आलेखीय विधि से हल करें : "],[x+3y-6=0,2x-3y-12=0]

9x+3y+12=0,18x+6y+24=0

Solve for x and y: 2x - 3y-13 =0 , 3x -2y+12 =0

निम्नलिखित समीकरणों को गुणनखंड विधि द्वारा हल करें- (2x)/(x-3)+1/(2x+3)+(3x+9 )/((x-3)(2x+3))=0

Find the area of triangle formed by the lines: x+y-6=0,x-3y-2=0 and 5x-3y+2=0

Find the equations of the bisectors of the internal angles of the triangle whose sides are : 3x + 4y -6 = 0, 12x -5y-3 = 0, 4x - 3y + 12 =0 .

The area (in sq units) of the quardilateral formed by the lines 2x + 3y + 6 = 0, 2x - 3y + 6 = 0, 2x + 3y - 6 = 0 and 2x - 3y - 6 = 0 is

The equation of the medians of a triangle formed by the lines x+y-6=0, x-3y-2=0 and 5x-3y+2=0 is

{:(2x + 3y + 5 = 0),(3x - 2y - 12 = 0):}

{:(2x + 3y + 5 = 0),(3x - 2y - 12 = 0):}

The lines x+2y-5=0, 2x-3y+4=0,6x+4y-13=0