If the ordinate of a point on the parabola `y^(2)`=4x is twic the latus rectum then the point is

If the ordinate of a point on the parabola y^(2)=4ax is twice the latus rectum, prove that the abscissa of this point is twice the ordinate.

" The ordinate of a point on the parabola " y^(2)=18x " is one third of its length of the latus rectum. Then the length of subtangent at the point is "

The ordinate of a point on the parabola y^2 =18x is one third of its length of the latus-rectum. Then the length of sub-tangent at the point is

A triangle formed by the tangents to the parabola y^(2)=4 a x at the ends of the latus rectum and the double ordinate through the focus is

The locus of the point of trisection of all the double ordinates of the parabola y^(2)=lx is a parabola whose latus rectum is - (A) (l)/(9)(B)(2l)/(9) (C) (4l)/(9) (D) (l)/(36)

The point of intersection of the normals to the parabola y^(2)=4x at the ends of its latus rectum is

The point of intersection of the normals to the parabola y^(2) =4x at the ends of its latus rectum is

The latus rectum of the parabola y^(2)=5x+4y+1 is

The triangle formed by the tangents to a parabola y^(2)=4ax at the ends of the latus rectum and the double ordinate through the focus is

Let A_(1) be the area of the parabola y^(2)=4ax lying between vertex and latus rectum and A_(2) be the area between latus rectum and double ordinate x=2a . Then A_(1)//A_(2)=