The SHM of a particle is given by the equation `x=2 sin omega t + 4 cos omega t`. Its amplitude of oscillation is

x = A cos omega t + B sin omega t , the amplitude of this wire is:

The displacement of a particle executing simple harmonic motion is given by y= A_(0) +A sin omega t+ B cos omega t . Then the amplitude of its oscillation is given by:

The motion of a particle is given by x = A sin omega t + B os omega t . The motion of the particle is

The displacement of a particle executing a S.H.M. is given by x= A "sin" omega t +A "cos" omega t . What is the amplitude of motion ?

The displacement of a SHM particle is y= 3 sin omega t+4 cos omega t then its amplitude will be……

The displacement equation of a particle of medium during wave mation is given by y=A sin omega t-B cos omega t The amplitude of the oscillator will be

The motion of a particle is given x = A sin omega t + B cos omega t The motion of the particle is

if the displacement of the particle at an instant is given by y = r sin (omega t - theta) where r is amplitude of oscillation. omega is the angular velocity and -theta is the initial phase of the particle, then find the particle velocity and particle acceleration.