For the circuit shown, with `R_1=1.0 Omega,R_2=2.0Omega,E_1=2V and E_2=E_3=4V` the potential difference between the points ‘a’ and ‘b’ is __________(in V)

For the circuit shown, with R_(1)=1.0Omega,R_(2)=2.0Omega,E_(1)=2V and E_(2)=E_(3)=4V , the potential difference between the points 'a' and 'b' is approximately (in V ):

In the given network of ideal cells and resistors, R_(1) = 1.0 Omega, R_(2) = 2.0 Omega, E_(1) = 2V and E_(2) = E_(3) = 4V . The potential difference between the point a and b is

In the circuit as shown in figure, E_(1)=2V , E_(2)=2V, E_(3)=1V, and R=r_(1)=r_(2)=r_(3)Omega . The potential difference between points A and B will be

In the circuit in figure E_1=3V, E_2=2V, E_3=1V and R=r_1=r_2=r_3=1Omega Find the potential differece between the points A and B and the currents through each branch.

In the circuit shown in fig. E_(1)=3V, E_(2)= 2V, E_(3)= 1V, R=r_(1)=r_(2)=r_(3)= 1 ohm . Find the potential difference between the points A and B and the currents through each branch.

In the circuit shown in fig E_1 = 3 volts, E_2 = 2volts, E_3 = 1volt and R = r_1 = r_2= r_3= 1 ohm. (i) Find the potential difference between the points A and B and the currents through each branch. (ii) If r_2 is short circuited and the point A is connected to point B, find the current through E_1, E_2, E_3 and the resistor R.