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When a current of (2.5 +- 0.5) ampere fl...

When a current of `(2.5 +- 0.5)` ampere flows through a wire, it develops a potential difference of `(20 +- 1)` volt, the resistance of the wire is

A

`(8 +-2)` ohm

B

`(8 +-1.5)` ohm

C

`(8 +- 0.5)` ohm

D

`(8 +-3)` ohm

Text Solution

Verified by Experts

The correct Answer is:
A
`R= (V)/(I)= (20)/(2.5)= 8ohm`
`(DeltaR)/(R)= (DeltaV)/(V)+ (DeltaI)/(I)= (1)/(20)+ (0.5)/(2.5)= (1)/(4)`
`:. DeltaR= (1)/(4) xx 8= 2ohm:. R= (8+-)ohm`
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