The mass and volume of a body are found to be `5.00 pm 0.05 kg " and "1.00 pm 0.05 m^3` respectively. Then, the maximum possible percentage error in its density is

Options

A. `6%`
B. `3%`
C. `10%`
D. `5%`

Answer

A

Explanation

Here, Mass of the body ,` M= 5.00 +- 0.05 kg`
Volume of the body, `V= 1.00+-0.05m^(3)`
Density, `rho= (M)/(V)`
Relative error in density is `(Deltarho)/(rho)= (DeltaM)/(M)+ (DeltaV)/(V)`
Percentage error in density is `(Deltarho)/(rho)xx 100= (DeltaM)/(M)xx100+ (DeltaV)/(V)xx100`
`= ((0.05)/(5)xx100)+ ((0.05)/(1)xx100)= 1%+ 5%= 6%`