If the error in measuring the radius of the sphere is 2% and that in measuring its mass is 3%, Then the error in measuring density of materials the sphere is:

Options

A. `5%`
B. `7%`
C. `9%`
D. `11%`

Answer

C

Explanation

`"Density"= ("Mass")/("Volume") :. rho= (M)/((4)/(3)piR^(3))= (3M)/(4piR^(3))`
`:.` The percentage error in density is
`(Deltarho)/(rho)xx 100= ((DeltaM)/(M)+3(DeltaR)/(R)) xx100`
`= 3%+3 xx 2%= 3%+6%= 9%`