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If E= energy, G= gravitational constant,...

If E= energy, G= gravitational constant, I= impulse and M = mass, the dimension of `(GIM^(2))/(E^(2))` is same as that of

A

time

B

mass

C

length

D

force

Text Solution

Verified by Experts

The correct Answer is:
A
`[E]= [ML^(2)T^(-2)], [G]= [M^(-1)L^(3)T^(-2)], [I]= [MLT^(-1)]`
`[(GIM^(2))/(E^(2))]= ([M^(-1)L^(3)T^(-2)][MLT^(-1)][M^(2)])/([ML^(2)T^(-2)]^(2))= [T]`
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