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The dimensional formula for the magnetic...

The dimensional formula for the magnetic field is

A

`[MT^(-2)A^(-1)]`

B

`[ML^(2)T^(-1)A^(-2)]`

C

`[MT^(-2)A^(-2)]`

D

`[MT^(-1)A^(-2)]`

Text Solution

Verified by Experts

The correct Answer is:
A

`"Magnetic field" = ("force")/("current" xx "Length")`
`= ([MLT^(-2)])/([M][L])= [MT^(-2)A^(-1)]`
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Knowledge Check

  • The dimensional formula for magnetic flux is

    A
    `[phi]=[M^(2)L^(1)T^(-2)A^(-1)]`
    B
    `[phi]=[M^(1)L^(2)T^(-2)A^(-1)]`
    C
    `[phi]=[M^(1)L^(-1)T^(2)A^(1)]`
    D
    `[phi]=[M^(1)L^(2)T^(2)A^(-1)]`
  • The dimensional formula for magnetic flux is

    A
    `[ML^(2) T^(-2) I^(-1)]`
    B
    `[ML^(2) T^(-2) I^(-2)]`
    C
    `[ML^(-2) T^(-2) I^(-1)`
    D
    `[ML^(-2) T^(-2) I^(-2)]`
  • The dimensional formula for magnetising field H is

    A
    `[M^(0) L^(-1) T^(0) A]`
    B
    `[M^(0) L T^(-3) A]`
    C
    `[M^(0) L TA^(-1)]`
    D
    `[M^(0) L^(1) T^(-1) A]`
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