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10^(12)alpha- particles (Nuclei of heliu...

`10^(12)alpha`- particles (Nuclei of helium) per second falls on a neutral sphere, calculate time in which sphere gets charged by `2mu C`.

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Number of `alpha`-particles falls on the neutral sphere in t second `= 10^(12) t`
Charge on `alpha`-particle = +2e, So
Charge incident in time `t = (10^(12)t) (2e)`
`because` Given charge is `2mu C`
`:. 2 xx 10^(-6) = (10^(12) t).(2e)`
`rArr t = (10^(-18))/(1.6 xx 10^(-19)) = 6.25` sec
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