A charged oil drop of mass `9.75 xx 10^(-15) kg` and charge `30 xx 10^(-16) C` is suspended in a uniform electric field existing between two parallel plates. The field between the plates is (take `g = 10 ms^(-2)`)

Options

A. `3.25 V m^(-1)`
B. `300 V m^(-1)`
C. `325 V m^(-1)`
D. `32.5 V m^(-1)`

Answer

D

Explanation

`E = (mg)/(q) = (9.75 xx 10^(-15) xx 10)/(30 xx 10^(-16)) = 32.5 Vm^(-1)`