On moving a charge of 20 coulomb by 2cm, 2J of work is done, then the potential difference between the points is

Options

A. 0.1 V
B. 8 V
C. 2 V
D. 0.5 V

Answer

A

Explanation

Potential difference between two points in an electric field is `V_(A) - V_(B) = (W)/(q_(0))`
where, W is work done by moving charge `q_(0)` from point A to B. Here, `W = 2J, q_(0) = 20 C` So, `V_(A) - V_(B) = (2)/(20) = 0.1 V`