Two capacitrors of `2 muF and 4 muF` are connected in parallel. A third capacitor of `6 muF` is connected in series. The combaination is connected across a 12 V battery. The voltage across `2 mu F` capacitor is

Options

A. 2V
B. 8V
C. 6V
D. 1V

Answer

C

Explanation

`C_(P) = 2+ 4 = 6 mu F`
`(1)/(C )= (1)/(6) + (1)/(6) = (2)/(6) = (1)/(3)`
or `C = 3 mu F`
Total charge,
`Q = CV = 3 xx 12 = 36 mu C`
Voltage across `6 muF` capacitor `= (36 muC)/(6muF) = 6V`
`:.` Voltage across each of `2mu F` and `4 muF` capacitor
`=12V - 6V = 6V`