The plates of a parallel plate capacitor have an area of `100cm^(2)` each and area separated by 2.5 mm. the capacitor is charged to 200V. Calculate the energy stored in the capacitor.

Options

A. `70.8 xx 10^(11) J`
B. `70.8 xx 10^(7) J`
C. `7.08 xx 10^(7) J`
D. `7.08 xx 10^(-7)J`

Answer

D

Explanation

`U = (1)/(2)CV^(2) = (1)/(2)(epsilon_(0)A)/(d)V^(2)`
`= (1)/(2) xx (8.85 xx 10^(-12) xx (100 xx 10^(-4)) (200)^(2))/(2.5 xx 10^(-3)) = 7.08 xx 10^(-7) J`