A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth's magnetic field is `0.2xx10^(-4)T`, then the emf developed between the two ends of hte conductor is

Options

A. `5mu V`
B. `5mV`
C. `50mu V`
D. `50mV`

Answer

C

Explanation

The emf developed between the end of the conductor is
`epsi = 1/2 omega B l^2 = 1/2 xx 5 xx 0.2 xx 10^(-4) xx (1)^2 `
` = 5 xx 10^(-5) V = 50 xx 10^(-6) V = 50muV`