A `0.1 m` long conductor carrying a current of `50 A` is perpendicular to a magentic field of `1.25 mT`. The mechanical power to move the conductor with a speed of `1ms^(-1)` is

Options

A. 62.5 mW
B. 625 mW
C. 6.25 mW
D. 12.5 mW

Answer

C

Explanation

Here , l = 0.1 m, v = `1ms^(-1)`
`I = 50A , B = 1.25 mT = 1.25 xx 10^(-3) T`
The mechanical power is
`P = epsi I =Bl v I = 1.25 xx 10^(-3) xx 0.1 xx 1 xx 50`
` = 6.25 xx 10^(-3) W =6.25 mW`