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An ac source is of (200)/(sqrt(2)) V, 50...

An ac source is of `(200)/(sqrt(2))` V, 50 Hz. The value of voltage after `(1)/(600)s` from the start is

A

200 volt

B

`(200)/(sqrt2) `volt

C

100 volt

D

50 volt

Text Solution

Verified by Experts

The correct Answer is:
C
`V_(rms) = (200)/(sqrt2) V_0 =sqrt2 V_(rms) = 200V`
`V = V_0 sin 2pi vt = 200 sin 2pi xx 50 xx 1/600 = 200 sin pi/6 = 100V`
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