Home
Class 12
PHYSICS
The relation between an ac voltage sourc...

The relation between an ac voltage source and time in SI units is `V=120 sin(100 pi t)cos (100 pi t) V`. The value of peak voltage and frequency will be respectively

A

120 V and 100 Hz

B

`(120)/(sqrt2)V` and 100 Hz

C

60V and 200 Hz

D

60 V and 100Hz

Text Solution

Verified by Experts

The correct Answer is:
D

`V = 120 sin(100pi t)cos (100pit)`
` = 60sin (200pit) (because sin 2theta = 2sin theta cos theta)`
Compare it with standard equation
`V = V_0 sin omega t `
We get , `V_0 = 60V`
and `omega = 200 pi " or " 2pi v = 200 pi " or " v = 100 Hz `
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION AND ALTERNATING CURRENTS

    MTG GUIDE|Exercise NEET CAFE TOPICWISE PRATICE QUESTIONS (AC CIRCUITS CONTAINING RESISTOR, INDUCTOR OR CAPACITOR)|3 Videos
  • ELECTROMAGNETIC INDUCTION AND ALTERNATING CURRENTS

    MTG GUIDE|Exercise NEET CAFE TOPICWISE PRATICE QUESTIONS (LC OSCILLATIONS)|35 Videos
  • ELECTROMAGNETIC INDUCTION AND ALTERNATING CURRENTS

    MTG GUIDE|Exercise NEET CAFE TOPICWISE PRATICE QUESTIONS (SELF AND MUTUAL INDUCTANCE)|19 Videos
  • DUAL NATURE OF MATTER AND RADIATION

    MTG GUIDE|Exercise AIPMT/ NEET MCQs|30 Videos
  • ELECTROMAGNETIC WAVES

    MTG GUIDE|Exercise AIPMT/NEET(MCQs)|15 Videos

Similar Questions

Explore conceptually related problems

The voltage of an AC supply varies with time (t) as V = 120 sin 100 pi t cos 100 pi t . The maximum voltage and frequency respectively are

The voltage of an AC supply varies with time (t) as V = 120 sin 100 pi t cos 100 pi t . The maximum voltage and frequency respectively are

The equation of an alternating voltage is V =100sqrt2 sin 100pit volt. The RMS value of voltage and frequency will be respectively

The voltage of A.C source varies with tiem according equation. V = 120 sin 100 pi t cos 100 pi t .Then the frequency of source is

An alternating voltage is represented by V=80 sin(100 pi t)cos(100 pi t) volt, What is the peak voltage?

The emf an source is given by the expression epsi=300 sin 314 t . Write the value of peak voltage and frequency of the source.

The voltage of an a.c. source varies with time according to relation E=120 sin 100pitcos100 pi t then

The voltage of an AC source varies with time according to the relation: E = 120 sin 100 pi t cos 100 pi t V . What is the peak voltage of the source?

If an alternating voltage is represented as v = 300 sin 600 t then the arms value of the voltage and the frequency are respectively :

A alternating voltage varies with time (t) as V=100sin(50pit) . The rms voltage and the frequency respectively, are