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If a circuit made up of a resistance 1 O...

If a circuit made up of a resistance 1 `Omega` and inductance 0.01 H, an alternating emf of 200 voit at 50 Hz is connected, then find the phase difference between the current and the emf in the circuit.

A

`tan^(-1) (pi)`

B

`tan^(-1) (pi/2)`

C

`tan^(-1) (pi/4)`

D

`tan^(-1) (pi/3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`tan phi = ((X_L)/( R))`
`X_L = omega L = (2pi v L) = (2pi) (50) (0.01) = pi Omega`
Also , `R = 1 Omega`
`therefore phi = tan^(-1) (pi)`
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Knowledge Check

  • In resonant circuits, at resonance, the phase difference between current and emf is

    A
    0
    B
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    C
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