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A transformer with efficiency 80% works ...

A transformer with efficiency `80%` works at `4 kW` and `100 V`. If the secondary voltage is `200 V`, then the primary and secondary currents are respectively

A

40 A, 16 A

B

16 A, 40 A

C

20 A, 40A

D

40 A, 20 A

Text Solution

Verified by Experts

The correct Answer is:
A
Efficiency of a transformer ` = (V_SI_S)/(V_P I_P)`
` rArr 80/100 = (P_O)/(4 xx 10^3) rArr P_O = 16/5 xx 10^3 W = 3200 W`
`rArr I_S = (P_O)/(V_S) = 3200/200 = 16A`
Also `P_I = I_PV_P`
`I_P = (P_I)/(V_P) = (4 xx 10^3 W)/(100V) = 40A`
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