An `AC` voltage is applied to a resistance `R` and an inductance `L` in series. If `R` and the inductive reactance are both equal to `3 Omega`, the phase difference between the applied voltage and the current in the circuit is

Options

A. `pi/6`
B. `pi/4`
C. `pi/2`
D. 0

Answer

B

Explanation

Here `R = 3 Omega`
Inductive reactance , `X_L = 3Omega`
In the phase difference between the applied voltage and the current in the circuit is
`tan phi = (X_L)/( R) = (3Omega)/(3Omega) = 1`
`phi = tan^(-1) (1) " or " phi = pi/4`