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An electromagnetic wave going through va...

An electromagnetic wave going through vacuum is described by
` E= E_0 sin(kx- omega t), B=B_0sin(kx-omega t)`.
Then

Text Solution

Verified by Experts

For electromagnetic waves, `c=(E_(0))/(B_(0))` but `(omega)/(k)=c`,
Hence `(E_(0))/(B_(0))=(omega)/(k)`
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