An electromagnetic wave going through vacuum is described by `vecE=E_(0)sin(kx-wt) and vecB=B_(0)sin(kx-wt)`. Which of the following equation is true?

Options

A. `E_(0)k=B_(0)omega`
B. `E_(0)omega=B_(0)k`
C. `E_(0)B_(0)=omegak`
D. `E_(0)=B_(0)`

Answer

A

Explanation

Equations of an electromagnetic wave
`E=E_(0)sin(kx-omegat)and B-B_(0)sin(kx-omegat)`
The relation between electric field `(E_(0))` and magnetic field `(B_(0))`
is `E_(0)=cB_(0)" …(i)"`
Velocity of light `(c)=upsilon lambda=(omega)/(2pi)lambda=(omega)/(k)" "("where "k=(2pi)/(lambda))`
Substituting this value of c in equation (i), we get
`E_(0)=(omega)/(k)B_(0) or E_(0)k=B_(0)omega`