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The electric field of an electromagnetic...

The electric field of an electromagnetic wave travelling through vaccum is given by the equation ` E = E_(0) "sin"(kx - omegat)` The quantity that is independent of wavelength is

A

`(k)/(omega)`

B

`komega`

C

`omega`

D

k

Text Solution

Verified by Experts

The correct Answer is:
A

`(k)/(omega)=((2pi)/(lambda))/(2piupsilon)=(1)/(c)`
Where c is the speed of electromagnetic wave in vacuum. It is constant whose value is `3xx10^(8)ms^(-1)`.
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