A stone S is on the bottom of a swimming pool. The depth of the lying pool is d and index of refraction of water is `mu`. What is the depth of the swimming pool visible to a normal eye ? Cheak the results with `d=6ft` and `mu=1.5`.

Explanation

To solve the problem of finding the apparent depth of a swimming pool with a stone at the bottom, we can follow these steps:

### Step 1: Understand the Concept of Apparent Depth
The apparent depth of an object submerged in a medium is the depth at which it appears to be when viewed from a different medium. In this case, we have a stone at the bottom of a swimming pool (in water) and we are viewing it from the air.

### Step 2: Use Snell's Law
According to Snell's law, when light passes from one medium to another, the relationship between the angles of incidence and refraction is given by:
\[ \mu \sin(i) = n \sin(r) \]
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