The intensity of the light coming from one of the slits in a Young's double slit experiment is double the intensity from the other slit. Find the ratio of the maximum intensity to the minimum intensity in the interference fringe pattern observed.

Explanation

`(I_("max"))/(I_("min"))=((sqrt(I_(1))+sqrt(I_(2)))^(2))/((sqrt(I_(1))-sqrt(I_(2)))^(2))`
Now, `I_(1)=2I_(2)implies(I_("max"))/(I_("min"))=((sqrt(2I_(2))+sqrt(I_(2)))/(sqrt(2I_(2))-sqrt(I_(2))))^(2)=((sqrt(2)+1)/(sqrt(2)-1))^(2)=34`