Home
Class 12
PHYSICS
An object is placed in front of a spheri...

An object is placed in front of a spherical mirror of focal length f. If x and x' recpectively represent the distance of the object and the image from the focus, then

A

`f=x+x'`

B

`f^(2)=x x`

C

`f=|x-x'|`

D

`f=x x`

Text Solution

AI Generated Solution

The correct Answer is:
To derive the relationship between the distances of the object and the image from the focus of a spherical mirror, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Mirror Formula**: The mirror formula is given by: \[ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} \] where \( v \) is the image distance, \( u \) is the object distance, and \( f \) is the focal length of the mirror. 2. **Define Distances from the Focus**: Let \( x \) be the distance of the object from the focus, and \( x' \) be the distance of the image from the focus. Thus, we can express: \[ u = x + f \quad \text{(since object distance is measured from the mirror)} \] \[ v = x' + f \quad \text{(since image distance is also measured from the mirror)} \] 3. **Substitute into the Mirror Formula**: Substitute \( u \) and \( v \) into the mirror formula: \[ \frac{1}{x' + f} + \frac{1}{x + f} = \frac{1}{f} \] 4. **Multiply through by \( (x' + f)(x + f)f \)**: To eliminate the fractions, multiply through by \( (x' + f)(x + f)f \): \[ f(x + f) + f(x' + f) = (x' + f)(x + f) \] 5. **Expand the Equation**: Expanding both sides gives: \[ fx + f^2 + fx' + f^2 = x'x + fx + fx' + f^2 \] 6. **Simplify the Equation**: Cancel out the common terms on both sides: \[ f^2 = x'x - fx - fx' \] 7. **Rearranging the Terms**: Rearranging gives: \[ x \cdot x' = f^2 + fx + fx' \] 8. **Final Relation**: Thus, we arrive at the relationship: \[ x \cdot x' = f^2 \] ### Conclusion: The derived relationship between the distances of the object and the image from the focus of a spherical mirror is: \[ x \cdot x' = f^2 \]

To derive the relationship between the distances of the object and the image from the focus of a spherical mirror, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Mirror Formula**: The mirror formula is given by: \[ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} ...
Promotional Banner

Topper's Solved these Questions

  • OPTICS

    MTG GUIDE|Exercise Check your NEET vitals|25 Videos
  • OPTICS

    MTG GUIDE|Exercise AIPMT/NEET|55 Videos
  • OPTICS

    MTG GUIDE|Exercise AIPMT/NEET|55 Videos
  • MAGNETIC EFFECTS OF CURRENT AND MAGNETISM

    MTG GUIDE|Exercise AIPMT/NEET (MCQs)|48 Videos

Similar Questions

Explore conceptually related problems

An object is placed in front of a concave mirror of focal length f as shown in figure. Choose the correct shape of the image.

An object is placed in from of a convex mirror of focal length 50 cm, if the image is one fourth the size of the object, the distance of the image from the mirror is

An object is placed infront of a convex mirror of focal length f. Find the maximum and minimum distance of two object from the mirror such that the image is real and magnified.

An object is placed in front of a concave mirror of focal length 20 cm. The image formed is three times the size of the object. Calculate two possible distances of the object from the mirror?

An object is placed in front of the concave mirror of focal length f. The magnification of the image became twice when the object distance is changed from 20 cm to 11 cm. Calculate the value of f.

An object is placed at 50 cm in front of a concave mirror of focal length 25 cm. What is the nature of the image produced by the mirror ?

MTG GUIDE-OPTICS-Topicwise Practice Questions
  1. An object is placed in front of a convex mirror of a radius of curvatu...

    Text Solution

    |

  2. Two objects A and B when placed in turn in front of a concave mirror o...

    Text Solution

    |

  3. An object is placed in front of a spherical mirror of focal length f. ...

    Text Solution

    |

  4. When an object is kept at a distance of 30cm from a concave mirror, th...

    Text Solution

    |

  5. The image formed by a spherical mirror is virtual. The mirror will be.

    Text Solution

    |

  6. If the lower half of a concave mirror's reflecting surface is made opa...

    Text Solution

    |

  7. An object is placed at 15 cm in front of a concave mirror whose focal ...

    Text Solution

    |

  8. An object placed in front of a concave mirror at a distance of x cm fr...

    Text Solution

    |

  9. A vessel of depth 2d cm is half filled with a liquid of refractive ind...

    Text Solution

    |

  10. The reflective index of water with respect to air is 4//3 and the refl...

    Text Solution

    |

  11. A plane glass slab is placed over various coloured letters. The letter...

    Text Solution

    |

  12. A ray of light is incident on a medium at an angle i. It is found tha...

    Text Solution

    |

  13. A ray incident at a point at an angle of incidence of 60^(@) enters a ...

    Text Solution

    |

  14. Light incident on a surface separating two media is partly reflected a...

    Text Solution

    |

  15. A ray of light strikes a glass plate at an angle of 40^(@). If the ref...

    Text Solution

    |

  16. A ray of light falls on a transparent sphere with centre at C as shown...

    Text Solution

    |

  17. Refractive indices of water an glass are 4//3 and 3//2 respectively. A...

    Text Solution

    |

  18. A plane mirror is placed at the bottom of the tank containing a liquid...

    Text Solution

    |

  19. The apparent depth of water in cylindrical water tank of diameter 2R c...

    Text Solution

    |

  20. A ray of light is incident on a glass slab of thickness t, at an angle...

    Text Solution

    |