A plane mirror is placed at the bottom of the tank containing a liquid of refractive index `mu`. P is a small object at a height h above the mirror. An observer O-vertically above P outside the liquid see P and its image in the mirror. The apparent distance between these two will be:

Options

A. `2muh`
B. `(2h)/(mu)`
C. `(2h)/(mu-1)`
D. `h(1+(1)/(mu))`

Answer

B

Explanation

Image formation by a mirror ( either plane or spherical) does not depended on the medium.
The image of P will be formed at a distance h below the mirror. If d=depth of the liquid in the tank,
apparent depth of `P=x_(1)=(d-h)/(mu)`.
apparent depth of the image of `P=x_(2)=(d+h)/(mu)`.
apparent distance between P and its image=x_(2)-x_(1)=(2h)/(mu)*`