A,B, and C are the parallel sided transparent media of refractive indices `n_(1),n_(2)` and `n_(3)` respectively. They are arranged as shown in the figure. A ray is incident at an angle `i` on the surface of separation of A and B which is as shown in the figure. After the refraction into the medium B the ray grazes the surfaces of separation of the media B and C. then `sin i` equal to

Options

A. `(mu_(3))/(mu_(1))`
B. `(mu_(1))/(mu_(3))`
C. `(mu_(2))/(mu_(3))`
D. `(mu_(1))/(mu_(2))`

Answer

A

Explanation

Applying Snell.s law at M,
`musintheta=mu_(2)sintheta` …(i)
Again, applying Snell.s law at N
`mu_(2)sintheta.=mu_(3)sin90^(@)`
`mu_(1)sintheta=mu_(3)` (Using(i))
`sintheta=(mu_(3))/(mu_(1))`