Critical angle of glass is `theta_(1)` and that of water is `theta_(2)`. The critical angle for water and glass surface would be `(mu_(g)=3//2, mu_(w)=4//3)`

Options

A. between `theta_(1)` and `theta_(2)`
B. greater than `theta_(2)`
C. less than `theta_(1)`
D. less than `theta_(2)`

Answer

B

Explanation

Here, `sintheta_(1)=(1)/(mu_(g))=(1)/(3//2)=0.6666`
and `sintheta_(2)=(1)/(mu_(w))=(1)/(4//3)=(3)/(4)=0.75`
As `mu_(g)gtmu_(w), :.theta_(1)lttheta_(2)`
If is the critical angle between glass and water, then
`sintheta=(mu_(w))/(mu_(g))=(4//3)/(3//2)=(8)/(9)=0.8888`
`:.thetagttheta_(2)`