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Critical angle for light going from medi...

Critical angle for light going from medium (i) to (ii) is `theta` . The speed of light in medium (i) is v then speed in medium (ii) is

A

`v(1-costheta)`

B

`(v)/(sintheta)`

C

`(v)/(costheta)`

D

`(v)/(1-sintheta)`

Text Solution

Verified by Experts

The correct Answer is:
B

`sintheta=(mu_(2))/(mu_(1))=(v)/(v.)`
Where v and v. are the speeds of light in medium (i) and medium (ii) respectively.
`v.=(v)/(sintheta)`
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