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The radii of curvatures of a double conv...

The radii of curvatures of a double convex lens are 15 cm and 30 cm, and its refractive index is 1.5. Then its focal length is -

A

`22` cm

B

`25` cm

C

`30` cm

D

`32` cm

Text Solution

Verified by Experts

The correct Answer is:
A

According to lens maker.s formula,
`(1)/(f)=(mu-1)((1)/(R_(1))-(1)/(R_(2)))`
For double convex lens, `R_(1)=+R,R_(2)=-R`
`(1)/(20)=(1.55-1)[(1)/((+R))-(1)/((_R))]implies(1)/(20)=(0.05)((2)/(R))`
R= `22` cm
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