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A ray of light is incident normally on one of the faces of a prism of apex angle `30^(@)` and refractive index `sqrt(2)`. The angle of deviation through prism is

A

`0^(@)`

B

`12.5^(@)`

C

`15^(@)`

D

`22.5^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C

For normal incidence,
`i=0^(@), r_(1)=0^(@)`
As `:.r_(2)=A-r_(1)=30^(@)`
As `mu=(sine)/(sinr_(2))`
`:.sine=musinr_(2)=sqrt(2)sin30^(@)-(1)/(sqrt(2))`
or `e=sin^(-1)((1)/(sqrt(2)))=45^(@)`
or `delta=i+e-A=0^(@)+45^(@)-30^(@)=15^(@)`
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