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The time required for the light to pass ...

The time required for the light to pass through a glass slab (refractive index=`1.5`) of thickness `4` mm is
(c=`3xx10^(8)` m `s^(-1)`, speed of light in free space)

A

`10^(-11)` s

B

`2xx10^(-11)` s

C

`2xx10^(11)` s

D

`2xx10^(-5)` s

Text Solution

AI Generated Solution

The correct Answer is:
To find the time required for light to pass through a glass slab of thickness 4 mm and refractive index 1.5, we can follow these steps: ### Step 1: Convert the thickness from mm to meters The thickness of the glass slab is given as 4 mm. To convert this to meters: \[ \text{Thickness} = 4 \, \text{mm} = 4 \times 10^{-3} \, \text{m} \] ### Step 2: Determine the speed of light in the glass slab The speed of light in a medium can be calculated using the formula: \[ v = \frac{c}{\mu} \] where: - \(c\) is the speed of light in vacuum (or air), which is \(3 \times 10^8 \, \text{m/s}\), - \(\mu\) is the refractive index of the medium (1.5 for glass). Substituting the values: \[ v = \frac{3 \times 10^8 \, \text{m/s}}{1.5} = 2 \times 10^8 \, \text{m/s} \] ### Step 3: Calculate the time taken to pass through the slab Using the formula for time, which is given by: \[ t = \frac{\text{Distance}}{\text{Speed}} \] we can substitute the thickness of the slab for distance and the speed of light in the glass for speed: \[ t = \frac{4 \times 10^{-3} \, \text{m}}{2 \times 10^8 \, \text{m/s}} \] ### Step 4: Perform the calculation Calculating the above expression: \[ t = \frac{4 \times 10^{-3}}{2 \times 10^8} = \frac{4}{2} \times 10^{-3} \times 10^{-8} = 2 \times 10^{-11} \, \text{s} \] ### Final Answer The time required for light to pass through the glass slab is: \[ t = 2 \times 10^{-11} \, \text{s} \]

To find the time required for light to pass through a glass slab of thickness 4 mm and refractive index 1.5, we can follow these steps: ### Step 1: Convert the thickness from mm to meters The thickness of the glass slab is given as 4 mm. To convert this to meters: \[ \text{Thickness} = 4 \, \text{mm} = 4 \times 10^{-3} \, \text{m} \] ...
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