Two slits, 4 mm apart, are illuminated by light of wavelength `6000 Å`. What will be the fringe width on a screen placed 2 m from the slits

Options

A. `0.12` mm
B. `0.3`mm
C. `3.0` mm
D. `4.0` mm

Answer

B

Explanation

`beta-(lambdaD)/(d)=(6000xx10^(-10)xx2)/(4xx10^(-3))=0.3xx10^(-3) m =0.3mm`.