In `YDSE` ratio of width of slit is `4:1`, then ratio of maximum to minimum intensity

Options

A. `2:1`
B. `4:1`
C. `9:1`
D. `8:1`

Answer

C

Explanation

`(W_(1))/(W_(2))=4=(I_(1))/(I_(2))=(a^(2))/(b^(2)):.(a)/(b)=2`
`(I_("max"))/(I_("min"))=((a+b)^(2))/((a-b)^(2))=(((a)/(b)+1)^(2))/(((a)/(b)-1)^(2))=((2+1)^(2))/((2-1)^(2))=(9)/(1)`