In a Young's double slit experiment, let `S_(1)` and `S_(2)` be the two slits, and C be the centre of the screen. If `angle S_(1)CS_(2)=theta` and `lambda` is the wavelength, the fringe width will be

Options

A. `(lambda)/(theta)`
B. `lambdatheta`
C. `(2lambda)/(theta)`
D. `(lambda)/(2theta)`

Answer

A

Explanation

Fringe width, `beta=(lambdaD)/(d)"and"theta=(d)/(D)`
`:.beta=(lambda)/(theta)`