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When a ray of light falls on a prism of ...

When a ray of light falls on a prism of angle `48^(@)` , it suffers minimum deviation. Refractive index of the material of prism is `1.6`. The angle of incidence is nearly

A

`16^(@)`

B

`48^(@)`

C

`30^(@)`

D

`41^(@)`

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The correct Answer is:
To solve the problem, we need to find the angle of incidence (i) when a ray of light passes through a prism with an angle of 48 degrees and a refractive index of 1.6, suffering minimum deviation. ### Step-by-Step Solution: 1. **Identify Given Values:** - Angle of the prism (A) = 48 degrees - Refractive index (n) = 1.6 2. **Use the Formula for Minimum Deviation:** The relationship between the refractive index, angle of incidence (i), angle of prism (A), and minimum deviation (Δm) is given by: \[ n = \frac{\sin(\Delta m + \frac{A}{2})}{\sin(\frac{A}{2})} \] 3. **Calculate \(\frac{A}{2}\):** \[ \frac{A}{2} = \frac{48}{2} = 24 \text{ degrees} \] 4. **Substitute Values into the Formula:** Plugging in the values into the refractive index formula: \[ 1.6 = \frac{\sin(\Delta m + 24)}{\sin(24)} \] 5. **Calculate \(\sin(24)\):** Using a calculator, we find: \[ \sin(24) \approx 0.4067 \] 6. **Rearranging the Equation:** Rearranging the equation gives: \[ \sin(\Delta m + 24) = 1.6 \times 0.4067 \approx 0.6507 \] 7. **Find \(\Delta m + 24\):** Now, we need to find the angle whose sine is approximately 0.6507: \[ \Delta m + 24 = \sin^{-1}(0.6507) \] Using a calculator, we find: \[ \Delta m + 24 \approx 40.514 \text{ degrees} \] 8. **Calculate \(\Delta m\):** Now, subtract 24 degrees from both sides: \[ \Delta m \approx 40.514 - 24 \approx 16.514 \text{ degrees} \] 9. **Use the Minimum Deviation Formula:** The relationship for minimum deviation is: \[ \Delta m = 2i - A \] Rearranging gives: \[ i = \frac{\Delta m + A}{2} \] 10. **Substituting Values:** Substitute \(\Delta m\) and \(A\) into the equation: \[ i = \frac{16.514 + 48}{2} \approx \frac{64.514}{2} \approx 32.257 \text{ degrees} \] 11. **Final Calculation:** Since we are looking for the angle of incidence when the prism suffers minimum deviation, we can round it to the nearest whole number: \[ i \approx 32 \text{ degrees} \] ### Conclusion: The angle of incidence is nearly **32 degrees**.
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