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The angular momentum of an electron in t...

The angular momentum of an electron in the hydrogen atom is `(3h)/(2pi)` Here. h is Planck's constant. The kinetic energy of this electron is

A

4.35 eV

B

1.51 eV

C

3.4 eV

D

6.8 eV

Text Solution

Verified by Experts

The correct Answer is:
B

`(3h)/(2pi)=n((h)/(2pi))` or `mv=(nh)/(2pir)`
Now, `r prop n^(2) therefore mv=p prop (nh)/(2pir)`
`p prop (h)/(2pin) or p prop (1)/(n)`
Energy, `E prop (1)/(n^(2))`
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