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The ratio of minimum to maximum waveleng...

The ratio of minimum to maximum wavelength in Balmer series is

A

`5:9`

B

`5:36`

C

`1:4`

D

`3:4`

Text Solution

Verified by Experts

The correct Answer is:
A

`(1)/(lambda_("max"))=R[(1)/(2^(2))-(1)/(3^(2))]=(5R)/(36)`
`(1)/(lambda_("mix"))=R[(1)/(2^(2))-(1)/(oo)]=(R)/(4)rArr (lambda_("min"))/(lambda_("max"))=(5R)/(36)xx(4)/(R )=(5)/(9)`
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