In the following radioactive decay, `""_(92)X^(232)rarr ""(89)Y^(220)` , how many `alpha` and `beta` particles are ejected from X to form Y ?

Options

A. 10, 6
B. 8, 8
C. 12, 6
D. 8, 6

Answer

D

Explanation

`""_(92)U^(238)rarr"_(82)Pb^(206)`
Let the number of `alpha and beta` particles emitted be x and y respectively. Then
`""_(92)U^(238)rarr""_(82)^Pb^(206)+x""_(2)He^(4)+ y ""_(-1)e^(0)`
Equating the mass and atomic numbers on both sides, we get
`206+4x=238 rArr x=(238-206)/(4)=8`
`82+2x-y=92 rArr y=82+2xx8-92=6`.
`therefore" "Te number of `alpha` and `beta` particles emitted are 8 and 6 respectively.