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A nucleus with Z =92 emits the following...

A nucleus with Z =92 emits the following in a sequence:
`alpha,beta^(-),beta^(-),alpha,alpha,alpha,alpha,alpha,beta^(-),beta^(-),alpha,beta^(+),beta^(+),alpha`. The Z of the resulting nucleus is

A

76

B

78

C

82

D

74

Text Solution

Verified by Experts

The correct Answer is:
B
Decrease in charge due to `4beta^(-)` emission `=4xx1=4`
Decrease in charge number due to `2beta^(+)` emission `=2xx1=2`
Net decrease in charge number `=16-4+2=14`
`therefore" Z of resulting nucleus "=92-14=78`
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