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An element A decays into element C by a ...

An element `A` decays into element `C` by a two-step process :
`A rarr B + ._2 He^4`
`B rarr C + 2 e overline`
Then.

A

A and C are isotopes

B

A and C are isobars

C

B and C are isotopes

D

A and B are isobars

Text Solution

Verified by Experts

The correct Answer is:
A
`""_(Z)A^(A) rarr""_(Z-2)B^(A-4)+""_(2)He^(4)`
`""_(Z-2)B^(A-4) rarr ""_(Z)C^(A-4) +2 ""_(-1)e^(0)`
Hence, A and C are isotopes.
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