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A uranium nucleus .(92)U^(238) emits and...

A uranium nucleus `._(92)U^(238)` emits and `alpha`-particle and a `beta`-particle in succession. The atomic number and mass number of the final nucleus will be

A

90, 233

B

90, 238

C

91, 234

D

93, 238

Text Solution

Verified by Experts

The correct Answer is:
C

When a radioactive nucleus emits an `alpha-` particle (a helium nucleus `""_(2)He^(4)`), its mass number decreases by 4 while the atomic number decreases by 2.
When a radioactive nucleus emits a `beta-` particle (an electron, `e^(-)`) its mass number remains unchanged while the atomic number increases by 1.
`therefore ""_(92)U^(283)overset(alpha)rarr ""_(90)^Th^(234) overset(beta)rarr ""_(91)Pa^(234)`
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